Y=0.1x^2-2x+12

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Solution for Y=0.1x^2-2x+12 equation: 



=0.1Y^2-2Y+12

We move all terms to the left:

-(0.1Y^2-2Y+12)=0

We get rid of parentheses

-0.1Y^2+2Y-12=0

a = -0.1; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-0.1)·(-12)
Δ = -0.8
Delta is less than zero, so there is no solution for the equation

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